Question

How many moles of O₂ are needed to react completely with 35.0 mol of FeCl₃? *

Answer 1

52.5 mol O2

Step-by-step explanation:

4 FeCl3 + 6 O2 -> 2 Fe2O3 +6 Cl2

4 mol FeCl3 -> 6 mol O2

35.0 mol FeCl3 -> x

x= (35.0 mol FeCl3 * 6 mol O2)/4 mol FeCl3

x=52.5 mol O2

Answer 2

Answer is A, 26.3 mol.