How many moles of AgCl2 are in 5.78x1024 molecules of AgCl2? a) 3.48x1048 moles AgCl2 b) 1375.87 moles AgCl2 c) 0.07 moles AgCl2 d) 9.60 moles AgCl2

Question

asked Dec 10, 2021 222k views

1 Answer

Rosencreuz · Answer 1 · 2021-12-13T17:42:39+0000

Answer:

9.6 mol AgCl2

Step-by-step explanation:

You have to use Avogadro's number: 6.023 x 10^23

5.78 x 10^24 molecules (1 mol AgCl2/ 6.023 x 10^23 molecules) =9.6 mol AgCl2