Question

A bag contains 2 red marbles, 2 green marbles, and 4 blue marbles. If we choose a marble, then another marble without putting the first one back in the bag, what is the probability that the first marble wl be red and the second will be green

Answer 1

1/4

Explanation:

There are 8 marbles 4 blue and the other half are red and green.

4 blue= 1/2

2 red= 1/4

2 green= 1/4

The red and the green both have a 1/4 chance.

Answer 2

Answer

Explanation:

There is a total of 8 marbles.

1. there are 2 red marbles in total so
`(2)/(8)` this can be simplify to
`(1)/(4)`

2. the probability of the second event is
`(2)/(7)`

for both event the probability will be

`(1)/(4)` ×
`(2)/(7)` =
`(1)/(14)`