Answer:
7.888m
Step-by-step explanation:
Given:
frequency 'f'= 90Hz
velocity of the sound 'v' = 340 m /sec
The wavelength of the wave is given by,
 λ= v/f => 340/90
 λ= 3.777m
The destructive interference condition is givn by
Δd= 
 λ
where, m=0,1,2,3,..
 
m=0, for minimum destructive interference
Δd= 
 x 3.777
Δd=1.888
Therefore, the required distance is
=
 + Δd => 6 + 1.888
= 7.888m
Thus, So the speaker should be placed at 7.888 m