Question

On a coordinate plane, a parabola opens up. It goes through (negative 3.25, 5), has a vertex of (1.75, negative 2.75), and goes through (6.25, 5). Solid circles appear on the parabola at (negative 3, 4), (0, negative 2), (1.75, negative 2.75), (3, negative 2), (6, 4). Which is f(6) for the quadratic function graphed? –2 –0.5 1.5 4

Answer 1

Answer: The answer is D: 4

Answer 2

(d) 4

Explanation:

The ordered pair (6, 4) tells you the function value f(6) is 4.

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Additional comment

There does not exist a parabola that will go through the points listed. Your parabola is symmetrical about x=1.5, not x=1.75.