Question

What is the equation for the equilibrium constant for this equation?

CO + 3H2 ⇌ CH4 + H2O
A. [CO][H2]3 / [CH4][H2O]
B. [CH4][H2O] / [CO][H2]3
C. [H2O][H2] / [CH4][CO]
D. [CH]4[H2O] / [H2]3

Answer 1

the equilibrium constant Kc is:

`Kc=([CH_(4) ]*[H_(2)O] )/([CO]*[H_(2) ]^(3) )` Option B

Step-by-step explanation:

Chemical balance is called the state of a system where no changes in the concentration of reagents or products are observed, over time, they remain constant. This occurs in reversible reactions, where the reaction rate of reagents to products is the same as that of products to reagents.

The chemical equation can be written in general as follows:

a A + b B → c C + d D

Where a, b, c, d are the stoichiometric coefficients of the reaction and A, B, C, D are the symbols or formulas of the different substances involved.

Kc is a constant for a specific reaction at a specific temperature that expresses the relationship between the molar concentrations (mol / l) of reactants and products in equilibrium:

`Kc=([C]^(c)*[D]^(d))/([A]^(a)*[B]^(b) )`

So, in the case of the reaction CO + 3H₂ ⇌ CH₄ + H₂O the equilibrium constant Kc is:

`Kc=([CH_(4) ]*[H_(2)O] )/([CO]*[H_(2) ]^(3) )`