Question

Calculate the amount of heat released when one bottle (250 g) of water is cooled from 30oC to 25oC. The specific heat of water is (4.186 J/g oC).

Answer 1

The amount of heat released is -5,232.5 J

Step-by-step explanation:

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

The amount of heat received or transferred by a body when it undergoes a temperature variation (Δt) without there being a change of physical state (solid, liquid or gaseous) is calculated by the expression:

Q = c * m * ΔT

Where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.

In this case:

• Q=?

• c=4.186
  `(J)/(g*C)`

• m= 250 g
• Δ=Tfinal - Tinitial= 25°C - 30°C= -5 °C

Replacing:

Q= 4.186
`(J)/(g*C)` *250 g* (-5°C)

Solvng:

Q= -5,232.5 J

The amount of heat released is -5,232.5 J