Question

A line passes through the points (4, 13) and (-2, -2). What is the equation of the line in standard form?

Answer 1

y=5/2x+3

Explanation:

easy. just find the slope and y-int.

slope is y2-y1 and under is x2-x1

Answer 2

Explanation:

`Slope=(y_(2)-y_(1))/(x_(2)-x_(1))\\\\=(-2-13)/(-2-4)\\\\=(-15)/(-6)\\\\=(5)/(2)`

m= 5/2

Equation: y - y1 = m(x -x1)

`y-13=(5)/(2)(x-4)\\\\y-13=(5)/(2)x-(5)/(2)*4\\\\y-13=(5)/(2)x-10\\\\y=(5)/(2)x-10+13\\\\y=(5)/(2)x+3`