Question

Calculate the volume in mL of 0.589 M NaOH needed to neutralize 52.1 mL of 0.821 M HCl in a titration.

Answer 1

72.6 mL

Step-by-step explanation:

A quick way to solve this titration problem when you have a monoprotic acid is to use the Dilution equation, M1V1=M2V2.

.589(x)=.821(52.1)

X=72.6 mL