How many moles of NF3 contain 2.55 x 10^24 Fluorine atoms?

Question

asked Apr 22, 2021 40.3k views

1 Answer

Zhekanax · Answer 1 · 2021-04-25T13:45:39+0000

Answer:

moles of O = atom / avogadro's number = 2.55*10^24 / 6.022*10^23 = 4.23 mol

since each N2O3 contains 3 O atoms:

moles of N2O3 = moles of O / 3 = 1.41 mol

Step-by-step explanation: