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Given: (x + 5)^2 + (y - 3)^2 = 144, where is the center of the circle? * (8, 5) (8, -5) (-5, 8) (5, 8)

Given: (x + 5)^2 + (y - 3)^2 = 144, where is the center of the circle? * (8, 5) (8, -5) (-5, 8) (5, 8)
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Given: (x + 5)^2 + (y - 3)^2 = 144, where is the center of the circle? *

(8, 5)

(8, -5)

(-5, 8)

(5, 8)

asked
User Msbyuva
by
8.3k points

1 Answer

2 votes

Answer:

8,5 that should be correct if it's not let me know

answered
User Mayuresh
by
7.6k points
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