Question

Which of the following 0.820 M solutions would have the greatest colligative effect?

A) SrCr2O7

B) C4H11N

C) K3PO4

D) Rb2CO3
Please explain how you know, thanks!

Answer 1

K3PO4

Step-by-step explanation:

Recall that colligative properties depends on the number of particles present. The greater the number of particles present, the greater the degree of colligative properties of the solution. Let us look at each option individually;

SrCr2O7-------> Sr^2+ + Cr2O7^2- ( 2 particles)

C4H11N (not ionic in nature hence it can not dissociate into ions)

K3PO4-------> 3K^+ + PO4^3- (4 particles)

Rb2CO3-------> 2Rb^+ + CO3^2- (3 particles)

Hence K3PO4 has the greatest number of particles and will display the greatest colligative effect.