Question

If a solution had an [OH-] = 3.00 x 10-10 moles/liter, what would be the pH value of this solution? 3.53 4.48

Answer 1

4.48

Step-by-step explanation:

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Answer 2

4.48

Step-by-step explanation:

p[OH-] = - log(3.00 *10^-10) = 9.52

pH + pOH = 14

pH = 14 - 9.52= 4.48