asked 178k views
0 votes
How many milliliters of a 0.215 molar solution are required to contain 0.0867 mol of NaBr

asked
User Ecnalyr
by
8.0k points

1 Answer

7 votes

Answer: 403ml

Step-by-step explanation:


M=(mol)/(L)

Solve for L;


L=(mol)/(M)\\L=(0.0867mol)/(0.215M)\\ L=0.403L

Convert to mililiters


0.403L((1000ml)/(1L))=403ml

answered
User FishingIsLife
by
8.1k points
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