Question

Crossed electric and magnetic fields are established over a certain region. The magnetic field is 0.669 T vertically downward. The electric field is 2.64 x 106 V/m horizontally east. An electron, traveling horizontally northward, experiences zero net force from these fields and so continues moving in a straight line. What is the electron's speed

Answer 1

The speed is
`v = 3.946 *10^6 \ m/s`

Step-by-step explanation:

From the question we are told that

The magnetic field is
`B = 0.669\ T`

The electric field is
`E = 2.64 *10^(6) \ V/m`

Generally the speed of the electron is mathematically represented as

`v = (E)/(B)`

Substituting values

`v = (2.64 *10^6)/(0.669)`

`v = 3.946 *10^6 \ m/s`