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How many grams of sodium fluoride (NaF) are dissolved in 3.75 L of a 1.55 M solution?

asked
User Frakon
by
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2 Answers

2 votes

Answer:244

Step-by-step explanation:

answered
User Silveris
by
7.9k points
4 votes

Answer: 244 g NaF

Explanation:

(3.75 L) x (1.55 mol/L NaF) x (41.98817 g NaF/mol) = 244 g NaF

Got this answer from Roger the Mole and it worked for me. (This is not my work and I don’t take credit)

answered
User BalusC
by
7.8k points
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