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Kapil is programming a robot to always know its distance from its charging base by following these steps: \qquad \text{Step }1)Step 1)start text, S, t, e, p, space, end text, 1, right parenthesis Save bbb, which is the current distance from the base. \qquad \text{Step 2})Step 2)start text, S, t, e, p, space, 2, end text, right parenthesis Face charging base and turn \theta^\circθ ∘ theta, degrees to the right. \qquad \text{Step 3)}Step 3)start text, S, t, e, p, space, 3, right parenthesis, end text Move xxx. \qquad \text{Step 4)}Step 4)start text, S, t, e, p, space, 4, right parenthesis, end text Compute new distance from the base. \qquad \text{Step 5)}Step 5)start text, S, t, e, p, space, 5, right parenthesis, end text Go back to step 111. For example, it might happen that when the robot gets to step 444 in its program, \qquad b = 70b=70b, equals, 70 units, \qquad \theta = 60^\circθ=60 ∘ theta, equals, 60, degrees, and \qquad x = 50x=50x, equals, 50 units. In the example above, what would the robot's new distance from its base be?

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2 votes

Answer:

The answer is 62

Explanation:

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User Delaram
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