An artist creates a cone shaped sculpture for an art exhibit. If the sculpture is 8 feet tall and has a base with a circumference of 21.352 feet, what is the volume of the sculp…

Question

asked Sep 14, 2021 106k views

1 Answer

Feyzi Bagirov · Answer 1 · 2021-09-20T22:02:34+0000

Answer:

Volume,
$V=96.79\ \text{feet}^3$

Explanation:

An artist creates a cone shaped sculpture for an art exhibit.

Height of sculpture is 8 feets

The circumference of base of the cone is 21.352 feet.

The base of a con is circular shaped. So,

$2\pi r= 21.352$

r is radius of cone

$r= (21.352)/(2* 3.14) \\\\r=3.4\ ft$

The volume of cone shaped sculpture is given by :

$V=(1)/(3)\pi r^2 h\\\\V=(1)/(3)* 3.14* (3.4)^2 * 8\\\\V=96.79\ \text{feet}^3$

So, the volume of the sculpture is
$96.79\ \text{feet}^3$ .