Question

A marshmallow has an initial volume of 0.033 L at standard pressure (1.0 atm). If the marshmallow is placed in a vacuum chamber and the final volume is 0.439L, what is the pressure inside the chamber?

Answer 1

0.075 atm

Step-by-step explanation:

P1V1 = P2V2

1.0 atm * 0.033L = P2 *0.439 L

P2 = 1*0.033/0.439 =0.075 atm