Question

A kite is flying at an angle of elevation of

about 55°. Ignoring the sag in the string,
find the height of the kite if 60 m of string
has been let out.
* help please *

Answer 1

49.15 m

Explanation:

Length of the string is the hupotenuse: 60

Height of the kite is the opposite: X

sin(55) = opposite/hypotenuse

sin(55) = X/60

X = 60sin(55)

X = 49.14912266 m