Question

a sample of oxygen occupies 75 L at 1 atm. If the volume double what is the new pressure of oxygen in atm

Answer 1

`P_2=(1)/(2) \text{ atm}`

Step-by-step explanation:

Considering ideal gas situation and initial condition as 1 and final condition as 2 all other conditions being constant we get

`P_1V_1=P_2V_2`

Here P1 = 1 atm , V1= 75L, also, V2=2V1 = 2×75 L =150 L

using above equation we have

`1*75=150* P_2\\P_2=(75)/(150) = (1)/(2) \text{ atm}`