Question

1. A cylinder of gas has a pressure of 4.40 atm at 25°C. At what temperature in °C

will it reach a pressure of 6.50 atm? Answer 167°C.

Answer 1

Answer: The final temperature in °C is 167

Step-by-step explanation:

To calculate the final temperature of the system, we use the equation given by Gay lussac's Law. This law states that pressure of the gas is directly proportional to the temperature of the gas at constant volume.

Mathematically,

`(P_1)/(T_1)=(P_2)/(T_2)`

where,

`P_1\text{ and }T_1` are the initial pressure and temperature of the gas.

`P_2\text{ and }T_2` are the final pressure and temperature of the gas.

We are given:

`P_1=4.40atm\\T_1=25^oC=(25+273)K=298K\\P_2=6.50atm\\T_2=?`

Putting values in above equation, we get:

`(4.40)/(298)=(6.50)/(T_2)\\\\T_2=440K=(440-273)^0C=167^0C`

Thus the final temperature in °C is 167