Question

Factor completely 2x^2+4x-2

Answer 1

2x^2+4x-2 = 2 * (x - 1 -
`√(2)`) * (x - 1 +
`√(2)`)

Explanation:

Factor completely 2x^2+4x-2

2x^2+4x-2 = 2* (x^2 + 2x - 1)

x = 1 + root( 4 - 4*(-1))/2

x = 1 + root(2)

and x = 1 - root(2)