Question

Matt and Taylor are taking a test. The test is designed to produce an overall mean score of 80, with a standard deviation of 6 for all test takers. Suppose Matt scored an 85 on the test and Taylor scored a 78 on the test. Given that the data is approximately normal, find the probability that another test taker, chosen at random, scored less than Matt and more than Taylor.

Answer 1

P (r) = 1/3

Explanation:

Matt 85 - 80 = +(5)

Taylor 80-78 = - (2)

+5-2 = 3 rise so deviation is the same.

Another test taker in 4 outcomes less than taylor more than taylor less than matt more than matt, would also be the same as AnB union.

So their are 3 outcomes = 1/3 = 0.333 rep.