Question

in the diagram below chords AB and CD intersects at E. If mAC=72 and mAEC=58. how many degrees are in mDB?

Answer 1

44°

Explanation:

∠ DEB and ∠ AEC are vertical and congruent

Thus ∠ DEB = 58°

The measure of the chord- chord angle DEB is half the sum of the measures of the arcs intersected by the angle and its vertical angle, that is

`(1)/(2)` (DB + AC ) = 58° ( multiply both sides by 2 )

DB + AC = 116°, that is

DB + 72° = 116° ( subtract 72° from both sides )

DB = 44°

Answer 2

Hey, and also, The Answer to Your question is 44 Degrees.

Explanation:

∠ DEB and ∠ AEC are vertical and congruent

Thus ∠ DEB = 58°

The measure of the chord- chord angle DEB is half the sum of the measures of the arcs intersected by the angle and its vertical angle, that is

(DB + AC ) = 58° ( multiply both sides by 2 )

DB + AC = 116°, that is

DB + 72° = 116° ( subtract 72° from both sides )

DB = 44°...... Stay safe Guys.