Question

A 1400 kg vehicle travelling at 22 m/s slows at a constant rate to 4.5 m/s in 6.75 s. What was the net force acting on the car during this time?

Answer 1

Net force = 3640 N

Step-by-step explanation:

From first equation of motion

V = U + at

4.5 = 22 + 6.75a

( 4.5-22) ÷ 6.75 = a

acceleration (a) = -2.6m/s^2 ( negative sign shows deceleration, but actual acceleration is 2.6)

But Force = mass × acceleration

Force = 1400 × 2.6

Force = 3640 N