How much energy is required to melt a 9.070kg (convert to grams first: 1kg=1000g) bag of ice at 0ºC? Write the formula and write answer with unit.

Question

asked Aug 15, 2021 38.2k views

1 Answer

Cdonner · Answer 1 · 2021-08-19T21:43:52+0000

Answer:

The energy required to melt 9.070 kg of ice is 3047520 J

Step-by-step explanation:

The mass, m of the ice = 9.070 kg = 907.0 g

The latent heat of fusion,
L_f ° for ice = 3.36×10⁵ J/Kg

Therefore we have the formula for the energy required to melt the mass m equals

$\Delta H = m * L_f$

Plugging in the values, we have;

ΔH = 3.36 × 10⁵ J/Kg×9.070 kg = 3047520 J or

ΔH = 3.36 × 10² J/g×9070 g = 3047520 J

Therefore, the energy required to melt 9.070 kg of ice = 3047520 J.