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What are the solutions of x2 -7x+13 = 0 ?

What are the solutions of x2 -7x+13 = 0 ?-example-1

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Answer:

x =(7-√-3)/2=(7-i√ 3 )/2= 3.5000-0.8660i

x =(7+√-3)/2=(7+i√ 3 )/2= 3.5000+0.8660i

Explanation:

Step by step solution :

Step 1 :

Trying to factor by splitting the middle term

1.1 Factoring x2-7x+13

The first term is, x2 its coefficient is 1 .

The middle term is, -7x its coefficient is -7 .

The last term, "the constant", is +13

Step-1 : Multiply the coefficient of the first term by the constant 1 • 13 = 13

Step-2 : Find two factors of 13 whose sum equals the coefficient of the middle term, which is -7 .

-13 + -1 = -14

-1 + -13 = -14

1 + 13 = 14

13 + 1 = 14

Observation : No two such factors can be found !!

Conclusion : Trinomial can not be factored

Equation at the end of step 1 :

x2 - 7x + 13 = 0

This may be a lot sorry it is confusing if it is wrong i'm so sorry don't come at me wrong please!

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User Kvnam
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