Question

Certain neutron stars (extremely dense stars) are believed to be rotating at about 0.83 rev/s. If such a star has a radius of 40 km, what must be its minimum mass so that material on its surface remains in place during the rapid rotation? Number Enter your answer in accordance to the question statement Units Choose the answer from the menu in accordance to the question statement

Answer 1

The mass of the star would be
`M = 2.644*10^(24) \ kg`

Step-by-step explanation:

From the question we are told that

The angular speed is
`w = 0.83\ rev/s = 0.83 * 2 \pi = 1.66 rad/s`

The radius of the star is
`r = 40km = 40 *1000 = 40 * 10^(3) m`

Generally the minimum mass of the start is mathematically evaluated as

`M = (r^3 w^2)/(G)`

Where is the gravitational constant with a values of
`G = 6.67*10^(-11) N \cdot m^2 /kg`

`M = ((40*10^3)^3 * 1.66^2)/(6.67*10^(-11))`

`M = 2.644*10^(24) \ kg`