Question

the volume of a gas at 155 kPa changes from 22 liters to 10 liters what is the new pressure if the temperature remains constant

Answer 1

341 Kpa

Step-by-step explanation:

P1V1=P2V2

P2= P1V1/V2

P2= (155 kPa*22L)/10L

P2=341 kPa