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What's the equation of the line that passes through the points (–8,4) and (0,22)?

What's the equation of the line that passes through the points (–8,4) and (0,22)?-example-1

1 Answer

4 votes

Answer:

C

Explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

calculate m using the slope formula

m =
(y_(2)-y_(1) )/(x_(2)-x_(1) )

with (x₁, y₁ ) = (- 8, 4 ) and (x₂, y₂ ) = (0, 22 )

m =
(22-4)/(0-(-8)) =
(18)/(0+8) =
(18)/(8) =
(9)/(4)

the line crosses the y- axis at (0, 22 ) ⇒ c = 22

y =
(9)/(4) x + 22 ← equation of line

answered
User Richhallstoke
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