asked 88.8k views
3 votes
An isosceles triangle has area of 110 ft. If the base is 14 ft, what is the length of each leg? Round your

answer to the nearest tenth.
Time Running
Artemot du May 22
1 Hour, 9 Minutes
21 ft
14.8 ft
17.2 ft
442.9 ft

asked
User Dalvtor
by
8.1k points

2 Answers

4 votes

Answer:

h=15,7 ft

l1=19.8

l2=l1=19.8

Explanation:

A=(b×h)/2

110=x×14/2

x×14=220

x=220/14=15,7

h=15.7 ft

l=rad(144+246.7)=19,8

l1=l2=19,8

answered
User Sasith
by
8.3k points
5 votes

Answer:

Explanation:

Area = 1/2*b*h

110 = 1/2 * 14 * h

15.714 = h

Pythagoren th

c^2 = a^2 + b^2

c^2 = 7^2 + (15.714)^2

c^2 = 49 + 246.93

c^2 = 295.93

c = 17.2

answered
User Besi
by
7.9k points

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