Answer:
a = 7
b = − 5 /2
Let's solve your system by substitution.
5a+4b=25 and 3a−8b=41
Rewrite equations:
5a+4b=25;3a−8b=41
Step: Solve5a+4b=25for a:
5a+4b=25
5a+4b+−4b=25+−4b(Add -4b to both sides)
5a=−4b+25
5a = −4b+25
5 a/5 = −4b+25 /5
(Divide both sides by 5)
a= −4 /5 b +5
Step: Substitute
−4 /5 b+5 for a in 3a−8b=41:
3a−8b=41
3( −4 /5 b+5)−8b=41
−52 /5 b+15=41 (Simplify both sides of the equation)
−52 /5 b+15+−15=41+−15 (Add -15 to both sides)
−52 /5 b=26
−52 /5 b /−52 /5 = 26 /−52 /5
(Divide both sides by (-52)/5)
b= −5 /2
Step: Substitute −5 /2 for b in a= −4 /5 b+5:
a= −4 /5 b+5
a= −4 /5 ( −5/ 2 )+5
a=7 (Simplify both sides of the equation)