Question

A car slows down from -27.7 m/s to -10.9 m/s while undergoing a displacement of -105 m. What was its acceleration?

Answer 1

Acceleration,
`a=3.08\ m/s^2`

Step-by-step explanation:

We have,

Initial speed of the car, u = -27.7 m/s

Final speed, v = -10.9 m/s

Displacement, d = -105 m

It is required to find acceleration of the car. Acceleration of an object is equal to the change in velocity divided by time.

The relation between displacement, velocity and acceleration is given by third equation of motion.

`v^2-u^2=2ad`

a is acceleration

`a=(v^2-u^2)/(2d)\\\\a=((-10.9)^2-(-27.7)^2)/(2(-105))\\\\a=3.08\ m/s^2`