Un electrón incide sobre una pantalla de televisión con una velocidad de 3 x 106 m/s. Si ha sido acelerado desde el reposo a través de una distancia de 0,04 m. ¿Cuál es su acele…

Question

asked Apr 15, 2021 114k views

1 Answer

Jason Parker · Answer 1 · 2021-04-20T05:30:48+0000

Answer:

Acceleration,
$a=1.12* 10^(14)\ m/s^2$

Explanation:

We have,

Initial speed of electron, u = 0

Final speed of electron,
$v=3* 10^6\ m/s$

Distance, d = 0.04 m

It is required to find the average acceleration of the electron. Let it is a. Using equation of motion as :

v^2-u^2=2ad

a = average acceleration

$v^2=2ad\\\\a=(v^2)/(2d)\\\\a=((3* 10^6)^2)/(2* 0.04)\\\\a=1.12* 10^(14)\ m/s^2$

So, the average acceleration of the electron is
$1.12* 10^(14)\ m/s^2$ .