Question

If s(x) = x – 7 and t(x) = 4x2 – x + 3, which expression is equivalent to (t circle s) (x)?

4(x – 7)2 – x – 7 + 3
4(x – 7)2 – (x – 7) + 3
(4x2 – x + 3) – 7
(4x2 – x + 3)(x – 7)

Answer 1

D

Explanation:

I am assuming that "circle" indicates multiplication

So first we must determine that the equation we need to solve is t(x) · s(x)

Now, we need to substitute t(x) and s(x) into our equation established above

Now our equation will look like

(4
`x^(2)`-x+3) · (x-7)

This of course is not the solved equation, but for the purposes of this answer, it is correct as that equation is equivalent to the original statement

Answer 2

4(x-7)²-(x-7)+3.

Explanation:

took the test :)