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Calculate the poH of a substance with [OH-] of 3.0 x 10^-6 M.

2 Answers

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answered
User David Valentine
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7.6k points
2 votes

Answer:

pOH = 5.52

Step-by-step explanation:

pOH= -log[OH] = -log[3.0 x 10^-6]

pOH= 5.52

answered
User Felix Grossmann
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