asked 73.8k views
1 vote
Find f'(x) f(x)÷1/(x-2)​

asked
User Zhorian
by
7.7k points

1 Answer

1 vote

Answer:

f'(x) =
-(1)/((x-2)^2)

Explanation:

f(x) = 1/(x-2) = (x-2)^(-1)

power rule + chain rule:

f'(x) = -(x-2)^(-2) * 1

f'(x) =
-(1)/((x-2)^2)

answered
User CAdaker
by
8.4k points

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