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Log2x (2x^2+8x-6) =2

Log2x (2x^2+8x-6) =2
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Log2x (2x^2+8x-6) =2

asked
User Steven Barnett
by
9.0k points

1 Answer

5 votes

Answer:


2x^3+8x^2-3x=0

Explanation:


2x (2x^2+8x-6)=2\\multiply-all-in-bracets-by-2x\\4x^3+16x^2-6x=2\\devide-all-by-2\\2x^3+8x^2-3x=0

answered
User MROB
by
7.9k points
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