Question

9. A gas occupies 8.2 L at 48°C and 750. torr. What volume will the gas occupy at STP?

Answer 1

Answer: The volume the gas will occupy at STP is 6.9 L

Step-by-step explanation:

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

`(P_1V_1)/(T_1)=(P_2V_2)/(T_2)`

where,

`P_1` = initial pressure of gas = 750 torr = 0.99 atm (760torr=1atm)

`P_2` = final pressure of gas = 1 atm (at STP)

`V_1` = initial volume of gas = 8.2 L

`V_2` = final volume of gas = ?

`T_1` = initial temperature of gas =
`48^oC=273+48=321K`

`T_2` = final temperature of gas =
`273K` (at STP)

Now put all the given values in the above equation, we get:

`(0.99* 8.2)/(321)=(1* V_2)/(273)`

`V_2=6.9`

Thus volume the gas will occupy at STP is 6.9 L