Question

What is the horizontal asymptote of j(X) = 14x^3 + 45/2x^3 +x+9 ?

Answer 1

y = 7

Explanation:

Since the biggest exponent on the top (numerator) and the bottom (denominator) are EQUAL...both are the third power in this question. Then just grab the coefficients (the number next to it, the 14 and below, the 2)

Keep them stacked the way you see them:

14/2 and write the equation. A horizontal line has the form y=

In this case, y = 14/2

y = 7

(jfyi if the top has a bigger exponent, then NO horizontal asymptote. If the bottom has a bigger exponent, then the H.A. is y = 0)