Question

If a bag contains 6 red balls, 4 green balls, and 3 blue balls. If we choose a ball, then another ball without putting the first one in the bag, what is the probability that the first ball is green anda the second one red

Answer 1

hello,

red 6

green 4

blue 3

• first ball is green:

`(4)/(13)`

• second ball is red:

`(6)/(12) = (1)/(2)`

The probability that these two events happen at the same time is:

`(4)/(13) * (1)/(2) = (4)/(26) = (2)/(13)`

`\boxed{crsjr}`