Question

You have a string with a mass of 0.0123 kg.0.0123 kg. You stretch the string with a force of 8.37 N,8.37 N, giving it a length of 1.81 m.1.81 m. Then, you vibrate the string transversely at precisely the frequency that corresponds to its fourth normal mode; that is, at its fourth harmonic. What is the wavelength ????4λ4 of the standing wave you create in the string? What is the frequency f4?

Answer 1

v= 35.09m/s

f= 38.77Hz

Step-by-step explanation:

Length 'L' = 1.81 m

Now, First off the fourth harmonic of a string with two nodes is given by:

L=2λ

1.81=2λ

λ= 1.81/2 =>0.905 m

Wave speed on a strecthed string is:

v=√(Ft/(m/l))

v= √(8.37)/(0.0123/1.81)

v= 35.09m/s

Next is to determine frequency i,e

v=λf or f =v/λ

f= 35.09/0.905

f= 38.77Hz