Question

A circle with area 36 pi has a sector with central angle of f 11/6 pi radians

Answer 1

33 π

Explanation:

Given,

Area of circle = 36 π

Central angle of sector,θ = 11/6 rad

Area of the sector = ?

we know,

A = π r²

36 π = π r²

r = 6

Area of sector

`A = (1)/(2) r^2 \theta`

`A = (1)/(2) * 6^2 * ((11)/(6)\pi)`

`A = 33\pi \ sqr. units`