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A concession stand sells hamburgers (h) for $2 and hotdogs (d) for $1. On Friday night they sold a total of 300 hamburgers and hotdogs and made $420. How many of each did they s…

A concession stand sells hamburgers (h) for $2 and hotdogs (d) for $1. On Friday night they sold a total of 300 hamburgers and hotdogs and made $420. How many of each did they s…
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A concession stand sells hamburgers (h) for $2 and hotdogs (d) for $1. On Friday night they sold a total of 300 hamburgers and hotdogs and made $420. How many of each did they sell?

Which system of equations matches the situation?

A concession stand sells hamburgers (h) for $2 and hotdogs (d) for $1. On Friday night-example-1
asked
User Slobobaby
by
7.9k points

1 Answer

1 vote

Answer:

the correct system of equations is the first one.

Explanation:

h+d=300

2h+d=420

answered
User Kit Ng
by
8.1k points
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