asked 116k views
3 votes
The net below can be folded to form a square pyramid.

A square pyramid. The square base has side lengths of 9 inches. The triangular sides have a height of 6.1 inches and side length of 7.6 inches.

What is the surface area of the pyramid?
190.8 square inches
217.8 square inches
300.6 square inches
354.6 square inches

asked
User JasonCG
by
7.4k points

2 Answers

5 votes

Answer:

190.8

Explanation:

answered
User Mehul Mali
by
8.2k points
5 votes

Answer:

190.8 square inches

Explanation:

The area of one of its triangular sides is given by A = bh/2 were b = base = 9 inches and h = perpendicular height = 6.1 inches.

A = bh/2. Since we have 4 triangular sides, the total area of its sides A₁ = 4A = 4bh/2 = 2bh = 2 × 9 × 6.1 = 109.8 square inches.

The area of is base is the area of a square = 9² = 81 square inches.

So te total surface area is 109.8 square inches + 81 square inches = 190.8 square inches

answered
User Roee Gavirel
by
8.8k points

No related questions found

Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.