Question

there are 15 popsicles in the freezer, 3 orange, 2 cherry, 4 lime, 2 grape, and 4 strawberry. what is the probability of selecting an orange, then a grape withot replacement?

Answer 1

1/35

Explanation:

Given: 15 to choose from, 3 are orange. 3/15 is the same as a one in five chance, so 1/5.

Now 14 left, two of them grape. A two in fourteen chance, the same as 1/7

Multiply the two fractions: 1/5×1/7= 1/35

Answer 2

.0286

The probability of selecting an orange than a grape without replacement is 2.86%.

Explanation:

P(Orange)*P(Grape) =

`(3)/(15) *(2)/(14) = .0286`

(since we already took out a popsicle the first time make sure to subtract it from the total when you pick the next one)