Question

A 32 g sample of LiCl is dissolved in water to for 655 mL of solution. What is the molarity of the solution?

1.1 x 10-3 M LICI
1.1 M LICI
4.9 x 10-2 M LICI
49 M LICI

Answer 1

The molarity of the LiCl solution is 1.15 M.

Step-by-step explanation:

To calculate the molarity of the solution, we first need to convert the mass of LiCl to moles using the molar mass of LiCl. The molar mass of LiCl is 6.94 g/mol + 35.45 g/mol = 42.39 g/mol. Therefore, the number of moles of LiCl is:

32 g ÷ 42.39 g/mol = 0.755 mol

Next, we divide the number of moles by the volume of the solution in liters to calculate the molarity:

0.755 mol ÷ 0.655 L = 1.15 M LiCl

Answer 2

Answer : The molarity of the solution is, 1.1 M LiCl

Explanation : Given,

Mass of
`LiCl` = 32 g

Volume of solution = 655 mL

Molar mass of
`LiCl` = 42.4 g/mole

Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.

Formula used :

`\text{Molarity}=\frac{\text{Mass of }LiCl* 1000}{\text{Molar mass of }LiCl* \text{Volume of solution (in mL)}}`

Now put all the given values in this formula, we get:

`\text{Molarity}=(32g* 1000)/(42.4g/mole* 655mL)=1.1mole/L=1.1M`

Therefore, the molarity of the solution is, 1.1 M LiCl