Question

Each blank is A,B,C,and D

Answer 1

B

D

A

Explanation:

`(4x^3 -4 + 7x) - (2x^3-x-8)`

To solve this first equation, we should get rid of the parenthesis. Getting rid of the second pair of parenthesis will mean flipping the signs of everything inside, since they are being subtracted. This will leave us with:

`4x^3 - 4 +7x - 2x^3 + x + 8`

Now we can combine like terms, and get:

`2x^3 + 8x + 4` <-- Answer B

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`(-3x^2 + x^4 + x) + (2x^4 - 7 + 4x)`

To solve the second equation, we should get rid of the parenthesis, just like how we did before. However, since we are adding, there is no need to flip the signs. This gives us;

`-3x^2 + x^4 + x + 2x^4 - 7 + 4x\\`

Now we can combine like terms, and get:

`3x^4 - 3x^2 + 5x - 7` <-- Answer D

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`(x^2 - 2x)(2x + 3)`

To solve this equation, we have to multiply the two terms together. To do this, we have to multiply both terms of one parenthesis by both terms of the other parenthesis. In numbers, this looks like:

`(x^2 * 2x)` +
`(x^2 * 3)` +
`(-2x * 2x)` +
`(-2x * 3)`

Now multiply each of those, and we get:

`2x^3 + 3x^2 - 4x^2 - 6x`

All we have left to do is combine the like terms, and we end with:

`2x^3 - x^2 - 6x` <-- Answer A

This was a super long, and a little confusing explanation. Let me know if this helped you, or if you need some more help!