Question

How many moles of Pb(NO3)2 are required

if 8 moles of AICI: are consumed?
3Pb(NO3)2 + 2AlCl3 + 3PbCl2 + 2A1(NO3)3

Answer 1

12 moles Pb(NO₄)₂ needed.

Step-by-step explanation:

3Pb(NO₃)₂ +2AlCl₃ => 3PbCl₂ + 2Al(NO₃)₃

Given => ? moles 8 moles

from reaction stoichiometry, 2 moles AlCl₃ requires 3 moles Pb(NO₄)₂ then 8 moles AlCl₃ requires 3/2(8) moles of the Pb(NO₄)₂ => 12 moles Pb(NO₄)₂ needed.